A box contains 70 cards numbered 1 to 70 if one card is drawn at random what is the probability that it bears a number divisible by 2 and 3
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total no of cards =70.
total no of cards between 1 to 70 which is divisible by both 3 and 2= 11
p(getting no divisible by 2 and 3)=11/70
total no of cards between 1 to 70 which is divisible by both 3 and 2= 11
p(getting no divisible by 2 and 3)=11/70
Answered by
20
Answer:
total no. of cards or possibilities =70
no. which are divisible by 2 and 3 = 11 ( 6,12,18,24,30,36,42,48,54,60, 66)
so, probability = 11/70
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