Question

A box contains 75 ticket numbered 1 to 75 . A ticket is drawn at random from the box
1. find number on ticket is divisible by 3 and 5​

Answer 1

Answer:15,30,45,60,75

Step-by-step explanation:

find out the numbers divisible by both 5 and 3

they are

15,30,45,60,75

Answer 2

The number on ticket is 15, 30, 45, 60, 75.

Step-by-step explanation:

A box contains 75 ticket numbered 1 to 75.

A ticket is drawn at random from the box.

Finding the number on ticket is divisible by 3 and 5.

If a number is divisible by 3 means sum of the digits of a number is divisible by 3.

If a number is divisible by 5 then it's unit digit must be 0 or 5.

So, the numbers between 1 to 75,

15, 30, 45, 60, 75 are divisible by 3 and 5

Hence, the number on ticket is 15, 30, 45, 60, 75.