A box contains 8 white balls and 4 black balls two balls are drawn randomly one by one until those of the same colour left in the box the probability that they wear white is
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the probability is 1/3 ie one upon three
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After 11 draws a white ball is left in the box. In the the first 11 draws we must get 7 white n 4black balls
So required probab 8C7into 4C4whole÷12C11 ie 2÷3
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