A box contains 80 discs numbered from 1 to 80. If one disc is drawn at random from the box,
find the probability that it bears.
[i]. a perfect square number.
[ii]. a number divisible by 2 and 3.
Answers
Answered by
3
Answer:
i} probability of a perfect square no.= 8 / 80 = 1 / 10
ii} probability of a no. divisible by 2 and 3 = 13 / 80
Answered by
3
Answer:
i) P(E) = no.of favorable outcomes/total no. of outcomes
Step-by-step explanation:
P(E)= No. of favorable outcomes/total no. of outcomes
i) E = perfect square ( which are 4,9,16,25,36,49,64.)
so, P(E) =7/80
ii) E = no.divisible by 2 and 3 (which are 6,12,18,24,30,36,42,48,54,60,66,72,78)
so, P(E) = 13/80
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