A box contains 9 green and 7 yellow balls. Two balls are drawn in succession at random
What is the probability that one of them is green and the other is yellow ?
(a) 2.1
(b)
is
(c) 21
(d)
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A box contains 9 green and 7 yellow balls. Two balls are drawn in succession at random the probability that one of them is green and the other is yellow is = 63/128
Step-by-step explanation:
The total number of balls contained in the box is:
= 9 + 7 = 16 balls
The probability of getting a green ball = 9/16
The probability of getting a yellow ball = 7/16
The probability that one of the balls drawn is green and the other one is yellow is given by:
P(yellow and green) = P(1st is yellow and 2nd is green) or P(1st is green and 2nd is yellow)
= P(7/16 × 9/16) + P(9/16 × 7/16)
P = 63/128
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