A box contains 9 tickets numbered 1 to 9 inclusive. If 3 tickets are drawn from the box one at a time, find the probability they are alternatively either odd, even, odd or even, odd ,even.
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Step-by-step explanation:
total num of tickets=9
if 3 tickets are drawn=9-3=6
p (odd no tickets)=
(1,3,5)
=3/9=1/3
p(even no tickets)=
(2,4,6)
=3/9=1/3
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