Question

A box contains 9 tickets numbered 1 to 9 inclusive. If 3 tickets are drawn from the box one at a time, find the probability they are alternatively either odd, even, odd or even, odd ,even.

Answer 1

Step-by-step explanation:

total num of tickets=9

if 3 tickets are drawn=9-3=6

p (odd no tickets)=

(1,3,5)

=3/9=1/3

p(even no tickets)=

(2,4,6)

=3/9=1/3