A box contains 90 cards bearing a number from 1 to 90. Find the probability that the card drawn bears (i) a two-digit number (ii) a perfect square number
Answers
Answered by
5
Answer:
Step-by-step explanation:
Total outcomes = 90
(i)two-digit numbers =(10,11,12......89,90)
P(two digit numbers)=81/90=9/10
(ii) perfect square= (1,4,9,16,25,36,49,64,84)
P(getting a perfect square)= 9/90= 1/10
Similar questions