a box contains 90 dics numbered from 1 to 90 dics is drawn at random from the box find the probability that it bears a prime number less than 23
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the answer is 23 by 90
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n(s)=90
prime numbers less than 23=2,3,5,7,11,13,17,19
p(P)=8/90=4/45
prime numbers less than 23=2,3,5,7,11,13,17,19
p(P)=8/90=4/45
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