Question

A box contains 90 discs . A disc is drawn at random . Find the probability that it bears a prime number less than 23​

Answer 1

Given,

A box contain 90 dics.

A disc is drawn random.

As per to the question,

Prime number less than 23 = 2,3,7,11,13,17,19

Total number of favorable outcomes = 8

Total number of outcomes = 90

Probability of getting odd number less than 23 =

$\frac{favorable \: number \: of \: outcomes}{total \: number \: of \: outcomes}$

= 8/ 90

= 4/45

Answer 2

Hey Buddy

Here's the answer

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Total no of discs = 90

Prime no less than 23 = { 2,3,5,7,11,13,17,19 } = 8

Probability = Favourable outcomes/ total no

=> Probability = 8 / 90

=> Probability = 4/45

HOPE HELPED

PEACE :)