A box contains 90 discs which are numbered from 1 to 90. If one discs is drawn at random from the box, find the probability that it bears (i) a two digit number (ii) a perfect square number (iii) a number divisible by 5.
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I) a two digit number = 9/10
II) a perfect square = 1/10
III) a number divisible by 5 = 2/10
Total number of discs present in the box = 90
Number of two digit numbered discs present in the box = 81
Probability of getting a two digit number = 81/90 = 9/10
Number of discs with perfect square = 9
Probability of getting a perfect square = 9/90 = 1/10
Number of discs that have numbers which are divisible by 5 = 18
Probability of getting a number divisible by 5 = 18/90
= 2/10
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