Question

A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from
the box, find the probability that it bears
a. a two-digit number
b). a perfect square number
c), a number divisible by 5.
d). a number divisible by 2 or 3.
e). a number divisible by 2 and 3.
f). a number divisible by 7
g). a number multiple of 8.
h), a two digit number divisible by 5.
i). a two digit number divisible by 2.
j). a two digit number divisible by 3.
​

Answer 1

Answer:

a. 80/90...8/9 exclude 90

b. 8/90

c. 17/90 exclude 90

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Answer 2

Answer:

a) 81/90 = 9/10

b) 9/90 = 1/10

c) 18/90 = 1/5

d) 60/90 = 2/3

e) 15/90 = 1/6

f) 12/90 = 2/15

g) 11/90 = 11/90

h) 16/90 = 8/45

i) 37/90 = 37/90

j) 21/90 = 7/30

Step-by-step explanation: