A box contains 90 discs which are numbered from 1 to 90. If one
disc is drawn at random from the box, find the probability that it
bears.
i) a two - digit number
ii) a perfect square number
iii) a prime number less than 15
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7
Answer:
i) Number of two-digit number =90−9=81, Total number =90
Probability of being a two-digit number =
90
81
ii) Since there are 9 perfect square numbers such that 1,4,9,16,25,36,49,64,81
Probability of being a perfect square =
90
9
=
10
1
iii) Since there are 12 numbers divisible of 7 such that 7,14,21,28,35,42,49,56,63,70,77,84
Probability of being a perfect square =
90
12
=
15
2
Step-by-step explanation:
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