Question

a box contains 90 dises numbered 1 to 90.if one dise is drawn at random from the box,find the probability that it bears a prime number less than 23​

Answer 1

Answer:

Step-by-step explanation:

probability of an event= no. of favourable outcomes divided by total no. of                            events

as the dies conatin 90 dice and total probabilitiy of getting prime no.s less than 23

therefore the prime nos less than 23 are

2,3,5,7,11,13,17,19 total of 8 prime nos.

so

P(getting prime no.s less than 23 ) =  8/90 = 4/45