Question

A box contains a large number of transistors, 30 per cent of which are type A and the rest

type B. A random sample of 4 transistors is taken. Determine the probabilities that i. all

of type A ii. all of type B iii. Two of type A and two of type B

iv. three of type A and one of type B.​

Answer 1

Answer:

I think A one......

Step-by-step explanation:

But not sure about the answer.

Answer 2

All are of type A when a random of 4 transistors are taken

Given:

A box contains a large number of transistors, A random sample of 4 transistors is taken.

To Find:

The probabilities of all the transistors which are mentioned

Solution:

To get the probabilities of the 4 transistors we get ,

All defective:

p = $\frac{4}{10}( \frac{4}{10})(\frac{4}{10})(\frac{4}{10})$

= $\frac{256}{10000}$

=0.0256

None defective:

P = $\frac{6}{10}(\frac{6}{10})(\frac{6}{10})(\frac{6}{10} )$

= 0.1296

Hence, All are of type A  when a random of 4 transistors are taken

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