A box contains balls and cubes that are either red or green. The balls make up 48% of all objects in the box. The ratio of red balls to green balls in the box is equal to the ratio of all red objects to all green objects in the box. Determine the ratio of red balls to red cubes in the box.
Answers
Answer:
Box A contains 6 red balls and 4 blue balls,
Probability of red in Box A = 6/10
and Box B contains 4 red balls and 8 blue balls.
Probability of red in Box B = 4/12
A die is rolled, if the number is less than 3, a ball is selected from box A.
Probability of getting 1,2 on dice = 2/6 = 1/3
If the result is 3 or more, a ball is selected from Box B.
Probability of getting 3-6 on dice = 4/6 = 2/3
What is the probability that the ball will be red and selected from Box B = 4/12*2/3 = 2/9
Answer:
x1/x2 = 0.9230
Step-by-step explanation:
Suppose total objects in the box = 100
Number of balls in the box = 48
Number of cubes in the box = 52
Assume the total number of red objects in the box = x
Same, the total number of green objects in the box = y
Red balls = x1 Red cubes = x2
Green balls = y1 Green cubes = y2
Total number of balls
x1 + y1 = 48 Equation (1)
Total number of cubes
x2 + y2 = 52 Equation (2)
Quantity Balance on the object w.r.t. to their colors
y = y1 + y2
x = x1 + x2
According to the given statement:
x1/y1 = x/y
Put replacement equation instead of 'x' and 'y'
x1/y1 = (x1 + x2)/(y1 + y2)
y1*x1 + x1*y2 = x1*y1 + x2*y1
x1*y2 - x2*y1 = 0
x1*y2 = x2*y1
x1/x2 = y1/y2
By Equation (1) and (2)
x1/x2 = (48-x1)/(52-x2)
By cross Multiplication
52x1-x1*x2 = 48x2-x1*x2
52x1 = 48x2
x1/x2 = 48/52
x1/x2 = 0.9230