Question

A box contains balls bearing numbers between 1 and 36. A ball is drawn from the box at random find the probability that the number of ball is (1) multiple of 3 or 5

Answer 1

Total no. of balls = 36

multiples of 3 & 5 are

3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36

5, 10, 15, 20, 25, 30, 35

Therefore total no. of multiples of 3 & 5 between 1 & 36 are 20

Therefore, p(getting a multiple of 3 & 5)

= 20/36

= 5/9

Hope this helps u...