Math, asked by a9mittytinottha, 1 year ago

A box contains cards bearing numbers from 6 to 70. If one card is drawn at random from the box, find the probablity that it bears (1) a one digit number(2) a number divisible by 5 (3) an odd number less than 30 (4) a composite number between 50 and 70 . Pls answer

Answers

Answered by ravikumarnarava
338
probability of getting a 1 digit no.=4/65
probability of  getting a no.divisible by 5=1/5
probability of getting a odd no.less than 30=12/65
probability of getting a composite no. between 50 and 70=14/65
Answered by adventureisland
129

Solution:

The formula for probability is  

\text {Probability}=\frac{\text {number of favorable events}}{\text {number of total events}}

From the given data in the question,

The total number of cards is 65;

a. Total number of one digit numbers in the cards is 4;  

\text { probability }=\frac{4}{65}

b. Total numbers divisible by 5 is 13;  

\text { probability }=\frac{13}{65}=\frac{1}{5}

c. Total number of odd numbers less than 30 is 12;

\text { probability }=\frac{12}{65}

d. Total number of composite numbers between 50 and 70 is 14;

\text { probability }=\frac{14}{65}

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