Question

A box contains cards bearing numbers from 6 to 70. If one card is drawn at random from the box, find the probability that it bears (1) a one digit number (2) a number divisible by 5

Answer 1

please refer the attachment

Answer 2

Box Contains Cards bearing Numbers from 6 to 70

Total Card=64

$\boxed{\mathbf{Probability=\frac{Favourable\: Outcomes}{Total\: Outcomes}}}$

(1)One Digit Numbers Are

=6,7,8,9

Total Favourable Outcomes=4

Total Outcomes=64

$\boxed{\mathbf{Probability(1\:Digit)=\frac{4}{64}}}$

$\boxed{\mathbf{Probability(1\:Digit)=\frac{1}{16}}}$

(2)Number Divisble by 5

10,15,20,25,30,35,40,45,50,55,60,65,70

Favourable Outcomes=13

Total Outcomes=64

$\boxed{\mathbf{Probability(D \:by\:5)=\frac{13}{64}}}$