Question

A box contains cards marked from 7 to 98. If one card is drawn at random from the box, find the

probability that the number bears (i) a single digit number (ii) multiple of 6 (iii) a factor of 50. please it's urgent​

Answer 1

convert this answer into ur answer

Single digit number cards = {1,2,3,4,5,6,7,8,9}=9

Total cards = 100

So, Probability  of getting single digit number = \frac{9}{100}1009

Perfect square number cards = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100} =10

So, probability of getting  number which is a perfect square = \frac{10}{100}=\frac{1}{10}10010=101

Number which is divisible by 7={7,14,21,28,35,42,49,56,63,70,77,84,91,98}=14

So, probability of getting  number which is divisible by 7 = \frac{14}{100}=\frac{7}{50}10014=507