A box contains cards numbered 11 to 123. A card is drawn at random from the box. Find the probability that the number on the drawn card is
(iii) one digit number
Answers
Answered by
0
Answer:
Cards in the number from 1 to 123
The perfect squares are : 16,25,36,49,64,81,100,121
Total numbers =113
Total perfect squares =8
⇒P( A square number) +
113
8
Multiple of 7 are :14,21,28,35,............119
Total multiples of 7=16
⇒P(A multiple of 7)=
113
16
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Answered by
1
Answer:
Total number of outcomes=123-10
= 113
Number of cards having single digit number = 0
(as card number starts from
11, not between 1 to 10)
So. total number of favourable outcomes=0
So, P(E)= Total number of favourable outcomes/total number of outcomes
= 0/113
= 0
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