Question

A box contains cards numbered 11 to 123. A card is drawn at random from the box. Find the probability that the number on the drawn card is 

(iii) one digit number​

Answer 1

Answer:

Cards in the number from 1 to 123

The perfect squares are : 16,25,36,49,64,81,100,121

Total numbers =113

Total perfect squares =8

⇒P( A square number) +

113

8

Multiple of 7 are :14,21,28,35,............119

Total multiples of 7=16

⇒P(A multiple of 7)=

113

16

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Answer 2

Answer:

Total number of outcomes=123-10

= 113

Number of cards having single digit number = 0

(as card number starts from

11, not between 1 to 10)

So. total number of favourable outcomes=0

So, P(E)= Total number of favourable outcomes/total number of outcomes

= 0/113

= 0

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