Math, asked by BinduShreep, 1 year ago

a box contains cards numbered from 1 to 17 a card is drawn at random from the box find the probability that the number of the card is a (a)prime number (b) a multiple of 3

Answers

Answered by RishabhRKO
17
Sample space = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17}

Total number of chances= 17
a) Prime numbers= 2,3,5,7,11,13,17
Number of favorable chances = 7
P(E) = 7/17
b) Multiple of 3 = 3,6,9,18,15
Number of favorable chances= 5
P(E) = 5/17
Answered by throwdolbeau
2

Answer:

Sample space of the following probability distribution = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17}

Total number of possible outcomes = 17

a) Prime numbers from 1 to 17 = 2, 3, 5, 7, 11, 13, 17

Number of favorable chances = 7

So, Required Probability = 7/17

b) Multiple of 3 from 1 to 17 = 3, 6, 9, 18, 15

Number of favorable chances = 5

So, Required Probability = 5/17

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