Question

A box contains cards numbered from 5 to 100 a card is picked up at random find the probability of getting a prime number number divisible by 2 or 3 perfect square numbers

Answer 1

Answer:

Step-by-step explanation:

Total outcomes=n(s)= 95

Therefore, let A be an event of getting prime number i.e

n(A)=23 (5,7,11,13,17,19,23,29,31,37,43,47,53,59,61,67,71,73,79,83,89 and 97)

Therefore p(A)= n( A)/n(S)

Substituting = 23/95

Let B be an event of getting square numbers

n(B)=8

Substituting = p(B)= n( B)/n(s)

=8/95

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