Question

a box contains counters marked with multiples of 2 less than 15 on them.what is the probability that a counter picked is a factor of 2.

Answer 1

Favourable outcomes=2,4,6,8,10,12,14
No.of favourable outcomes=7
P(getting a counter marked with factor of 2)=No.of favourable outcomes/Total no.of outcomes
=1/7

Answer 2

The probability of getting a factor of 2 is $\frac{7}{15}$

Step-by-step explanation:

Given Data

Number of counters marked with numbers in a box = 15

Find the probability of getting a factor of 2

Favourable outcomes of 2 from the box with counters marked in numbers from 1 to 15 is

A = {2, 4, 6, 8, 10, 12, 14}

Number of possibilities n(A) = 7

Total number of outcomes n(S) = 15

$P(A) = \frac{n(A)}{n(S)}$

$P(A) = \frac{7}{15}$

The probability of getting a factor of 2 from a box of counters marked in numbers from 1 to 15 is  $\frac{7}{15}$

To Learn More ...

1) 17 cards numbered 1,2,3........17 are put in a box and mixed thoroughly. One person draws as ard from the box. Find the probability that a number on the card is (i) odd (ii) even(iii) prime(iv) divisible by 3 and 2.

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