Question

a box contains four red, two white and three green marbles, all of which are the same size.Two marbles are selected one after the other from the box, without replacement. what is the probability that the marbles are of same colour?​

Answer 1

Answer:

number of red marbles = 4

number of white = 2

number of green = 3

probability = 4C1/9C1 ×3C1/8C1(red) + 2C1/9C1×1C1/8C1(white)+3C1/9C1×2C1/8C1(green)

first ball is drawn where total balls 9

second ball is drawn where total ball 9-1= 8

P total = 12/72+ 2/72+ 6/72 = 20/72 = 5/18 = 0.277

approximately = 0.28 ( YOUR ANSWER)

Step-by-step explanation:

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Answer 2

Answer:

5/18 = 0.28

Step-by-step explanation:

Given,

Number of red marbles = 4

Number of white marbles = 2

Number of green marbles = 3

Total balls are 4 + 2+ 3 = 9

To find,

the probability that the marbles are of same colour

Solution,

Probability of any 2 marbles of same colour

=> Probability of two red marble one after the other =  ⁴C₁/⁹C₁ × ³C₁/⁸C₁

=> Probability of two white marble one after the other =  ²C₁/⁹C₁ × ¹C₁/⁸C₁

=> Probability of two green marble one after the other =  ³C₁/⁹C₁ × ²C₁/⁸C₁

So, the probability that the marbles are of same colour = Probability of two red marble one after the other + Probability of two white marble one after the other  + Probability of two green marble one after the other

$\text {The probability that the marbles are of same colour = }\\\\=> \frac{4}{9} \times \frac{3}{8} + \frac{2}{9} \times \frac{1}{8} + \frac{3}{9} \times \frac{2}{8} \\\\=> \frac{(12 + 2+6)}{72} \\\\=> \frac{20}{72} \\\\=>\frac{5}{18}$

Hope it helps

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