Math, asked by jrmanvith6682, 11 months ago

A box contains n coins m of which are fair and rest are biased


Anonymous: ___k off

Answers

Answered by nishajoshi1298
0

let E1 be the event that the coin drawn is based. so, P (E1)= m/n , P(E2)= N- m/n. A is the event that on tossing the coin head appears first and then appears fail. so ,

Attachments:
Similar questions