A box contains slips numbered prime numbers from 1 to 10 and another box contains odd numbers from 1 to 10 lf one slip is taken from each.
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If we draw one slip from each box, total number of possible pairs=10×10=100
Prime numbers between 1 and 10 are 2,3,5 and 7.
Thus, there are 4 prime numbers in each box.
⇒ Number of pairs such that two slips are prime =4×4=16
Thus, probability that both the slips are prime =16/100
->4/25
Prime numbers between 1 and 10 are 2,3,5 and 7.
Thus, there are 4 prime numbers in each box.
⇒ Number of pairs such that two slips are prime =4×4=16
Thus, probability that both the slips are prime =16/100
->4/25
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