a box contains slips of all three digits numbers how many slips does have
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Step-by-step explanation:
If you had meant you have a sequence of slips, labelled between 3 and 32, then the result differs. You can put them into {3,4,…,32}, with order 32–3+1=30. And since you have asked about a slip labelled with a multiple of 4, then you can consider k=1,2,… for 4k in {3,4,…,32}. Find the last k. Then you will have the number of slips, multiple of 4, from a proposed sequence of slips. As usual for probability, you can divide the #favorable by the #possibilities. The numerator and denominator vary on interpretation, yet they will satisfy axioms.
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Answer:
the slips must have containing no. from 100 to 999.
Hence 999-100=899+11=900 slips
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