Question

A box contains some blue and some green balls. Another box contains 10 blue and 12 green balls. A ball
is removed from the first box and placed in the second box A ball is now removed from the first box.
What is the probability that the ball is blue?
1. The first box contains as many blue balls as the second box contains green balls.
II. The first box contains a total of 20 blue and green balls in the ratio 32 respectively
if the question can be answered with the help of any one statement alone, but not with the help of the
other statement alone,
if the question can be answered with the help of both statements together
if the question cannot be answered even with the help of both statements together
if the question can be answered with the help of either statement alone.​

Answer 1

2nd statement alone is enough

Step-by-step explanation:

Question can be solved with the help of 2nd  statement

. The first box contains a total of 20

 blue and green balls in the ratio 3:2respectively

Blue Balls = (3/5) 20 = 12

Green Balls = (2/5) 20 = 8

1st Statement given only Blue Balls = 12  , no information about green balls

Hence 2nd statement alone is enough

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