A box contains some green and blue balls 5 red balls are addded to that box and then a ball is taken from it. The probability of that ball being red is 5/22 and the probability of it being blue is 1/2? What is the total number of balls in the box?
Answers
Answer:
Correct option is
A
10
Let number of blue balls in the bag =x
Total no of balls in bag =5+x [No. of redball =5]
Probability of drawing a blue ball =
Total no of ball
No. of blue ball
P(B)=
5+x
x
Probability of drawing a Red ball =
Total no of ball
No. of red ball
P(R)=
5+x
5
Given,
P(B)=2P(R)
5+x
x
=2(
5+x
5
)
x=10
Hence, no. of blue balls in the bag =10.
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The answer is 22
Given: A box contains some green and blue balls
5 red ball are added to that box
The probability of getting red ball = 5/22
The probability of getting blue = 1/2
To find: Total number of ball in box
Solution:
Let x be the number of ball in box and 5 red balls adde
⇒ total number ball = x+5
The probability of getting red ball
= no of red ball / total number of balls = 5/ x+5
From given data =
⇒ 5(x+5) = 5 (22)
⇒ x + 5 = 22
⇒ x = 17
Therefore, total number of balls in bag = 22
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