A box contains some identical red coloured balls, labelled as A, each weighing 2 grams. Another box contains identical blue coloured balls, labelled as B, each weighing 5 grams. Consider the combinations AB, AB2 ,A2B and A2B3 and show that law of multiple proportions is applicable.
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AB mass of A = 2 g mass of B = 5 g hence if mass of A = 1g , mass of B = 5/2 g =2.5
inAB2 mass of A = 2g and mass of B= 10g , hence for 1 g A , mass of b = 10/2g =5
in A2B , mass of A = 4g , mass of B= 5g , hence for 1 g A , mass of B = 5/4g = 1.25
in A2B3 , mass of A = 4 g , mass of B= 15 g , hence for 1 g A mass of B = 15/ 4 g =3.75
therefore ratio of mass of B in all componds with the same amount of A =
2: 4 : 1: 3, which is a whole no. ratio hence law of multiple proportion.
inAB2 mass of A = 2g and mass of B= 10g , hence for 1 g A , mass of b = 10/2g =5
in A2B , mass of A = 4g , mass of B= 5g , hence for 1 g A , mass of B = 5/4g = 1.25
in A2B3 , mass of A = 4 g , mass of B= 15 g , hence for 1 g A mass of B = 15/ 4 g =3.75
therefore ratio of mass of B in all componds with the same amount of A =
2: 4 : 1: 3, which is a whole no. ratio hence law of multiple proportion.
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