Question

 A box contains three types of chocolates. Each type has 6 pieces. what is the probability that the chocolate selected at random will be of type first ?​

Answer 1

Answer:

1/3

Step-by-step explanation:

each type has 6 pieces &

box contains 3 types so the total number of chocolates = 6×3

= 18

so, first type has 6 pieces and total chocolates are 18.

probability of an event = (no. of favourable outcomes) / (no. of possible outcomes)

or

p(a) = n(e) / n(s)

n(e) = no. of favourable outcomes

n(s) = no. of possible outcomes

n(e) = {6}

n(s) = {18}

p(type first) = 6/18

= 1/3 (ans.)