Question

a box going down an inclined plane has an acceleration of 0.9m/s². calculate the distance covered by the box , 6 second after the start.

Answer 1

u=0

a=0.9 m/s²

t=6s

v=?

displacement=?

v=u+at

=0+0.9×6

=5.4 m/s

2as=v²-u²

=>2as=(5.4)²-(0)²

=>1.8s=5.4×5.4

=>s=3×5.4

=>s=16.2