Question

A box has 390 bulbs. Out of this 26 are defective. A bulb is chosen at

random. Find the probability of the bulbs chosen not being defective.

[A] 1/15

[B] 14/15

[C] 3/20

[D] 2/20​

Answer 1

Step-by-step explanation:

A box has 390 bulbs.

Out of this 26 are defective

Bulb chosen, not being defective =390−26=364

The probability is P(E)=

390

364

=

15

14

Answer 2

Answer:

A box has 390 bulbs.

Out of this 26 are defective

Bulb chosen, not being defective =390−26=364

so the probability is

$p(e) = \frac{364}{390} = \frac{14}{15}$

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