Question

A box has 390 bulbs. Out of this 26are defective . A bulb is chosen as random. The chance that it will not be defective is

Answer 1

total no. of bulbs =390
defective =26
and not defective =390-26=364
so the probability of not defective bulbs is
364/390
182/195 ans. hope this helps u

Answer 2

A = event that non defective bulb os selected
P(A)=m/n
m=390-26
m=364
n=390


P(A)=364/390
=182/195
0.93
Hope it helps..
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