Question

A box has 6 red and 3 black Marbles one marble is selected at random find the probability that the selected marble is red​

Answer 1

Sample Space = { 1R, 2R, 3R, 4R, 5R, 6R, 1B, 2B, 3B }

n(S) = { 9 }

°Let event 'A' be of getting red marble.

A = { 1R, 2R, 3R, 4R, 5R, 6R }

n(A) = { 6 }

Now the probability is:

p(A) = n(A)/n(S)

= 6/9

= 2/3

So the probability of getting red marble is 2:3

Thanks! Here's your answer

Answer 2

Answer: 2/3

Step-by-step explanation:

n(S) = 6 + 3

= 9

Let A be the event where the selected marble is red.

n(A) = 6

p(A)= n(A)/n(S)

= 6/9

= 2/3

Hope it helps...

Mark me as brainliest:)