A box has 8 red and 8 green balls. Two balls are drawn randomly in successive from box without replacement .The probability that the selected set contains one red and one green balls?
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total no. of balls=16
red balls=8
green balls=8
p(one red and one green)=2/16
p(one red and one green)=8
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total number of ball is 16
therefore,
red ball is 8
green ball is 8
probability of two successive balls = 2/16
probability of elected set contains one red and one green balls = 8
therefore,
red ball is 8
green ball is 8
probability of two successive balls = 2/16
probability of elected set contains one red and one green balls = 8
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