Math, asked by siddharth3249, 1 year ago

A box has 8 red and 8 green balls. Two balls are drawn randomly in successive from box without replacement .The probability that the selected set contains one red and one green balls?

Answers

Answered by simrangautam25
0

total no. of balls=16

red balls=8

green balls=8

p(one red and one green)=2/16

p(one red and one green)=8

Answered by alok7858
0
total number of ball is 16

therefore,
red ball is 8

green ball is 8

probability of two successive balls = 2/16

probability of elected set contains one red and one green balls = 8
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