Question

A box has a length of 18.1 cm and a width of 19.2 cm, and it is 20.3 cm tall.

a) What is the volume?
b) How precise is the measure of length? Of volume?
c) How tall is a stack of 12 of these boxes?
d) How precise is the measure of the height of one box? of 12 boxes?

Answer 1

Answer:

by the way nice dp...........

Answer 2

The volume of a box is $7.05X10^{-3} m^{3}$.

The height of 12 boxes is $2.44m$.

Given,

length of the box, l=18.1 cm

width (or breadth) of the box, b=19.2 cm

height of the box, h=20.3 cm.

To find,

the volume, height of the stack of 12 of these boxes.

Solution:

a)Volume is the measure of the occupied three dimensional space. It is the product of length, breadth (or width) and height.

$v=lXbXh\\v=18.1X19.2X20.3\\v=7054.656 cm^{3}$

b)Length would be more precise if its written in its S.I. unit. The S.I. unit of length is metre(m).

$l=18.1 cm\\l=\frac{18.1}{100} m\\l=0.181 m$

Now rounding it off to two decimal places,

$l=0.181m\\l=0.18m$

This volume would be more precise if it will be written in scientific notations and in its S.I. unit. The S.I. unit of volume is $m^{3}$.

Thus,

$v=7054.656 cm^{3} \\v=\frac{7054.656}{10^{6} } m^{3} \\v=0.007054656 m^{3} \\v=7.054656X10^{-3} m^{3}$

Now rounding it off up to two decimal places,

$v=7.05X10^{-3} m^{3}$

c)Height of 12 of these boxes=2.436 m.

$=12X 20.3 cm\\=243.6 cm\\=\frac{243.6}{100} m\\=2.436 m$

d)Height of one box will be precise when written in S.I. unit.

$h=20.3 cm\\h=\frac{20.3}{100}m \\h=0.203 m$

Rounding its value up to two decimal places,

$h=0.203m\\h=0.20 m$

Height of 12 boxes will be precise when it is rounded off to two decimal places.

$h=2.436m\\h=2.44m$

#SPJ2