Question

A box has cards numbered 14 to 99. Cards are mixed thoroughly and a card is drawn from the bag at random. Find the probability that the number on the card, drawn from the box is
(i) an odd number,
(ii) a perfect square number,
(iii) a number divisible by 7

Answer 1

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Answer 2

Explanation:

Total number of cards numbered (a=14) to (b=99) in the box (S)=(b-a+1)

=99-14+1 = 86

i) Let E be the event of getting

an odd number on the card .

Then , the outcomes favourable to E are 15,17,19,...,99 .

Therefore, the number of outcomes favourable to E = 43

So, P(E) = 43/86 = 1/2

ii) Let E be the event of getting

a perfect square number on the

card .

Then, the outcomes favourable to E are 16,25,36,49,64,81.

Therefore,

the number of outcomes to favourable to E is 6.

P(E) = 6/86 = 3/43

iii) Let E be the event of getting

a number divisible by on the card.Then , the outcomes favourable outcomes to E are

14,21,28,.....98.

Therefore,

the number of outcomes to favourable to E = 13

P(E) = 13/86

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