A box has cards with numbers 21, 22, 23…….40. A card is chosen at
random. What is the probability that the card chosen at random is
i) A prime number
ii) Sum of the digits is a multiple of 3
iii) Divisible by 4 or 5.
Answers
Given:
The possible outcomes are:
21, 22, 23, ……., 40
Total number of possible outcomes = 20
Solution:
i) A prime number
The prime numbers between 21 to 40:
23, 29, 31 and 37
Number of favourable outcomes = 4
∴ Probability(getting a prime number) =
= or,
ii) Sum of the digits is a multiple of 3
The sum of the digits is a multiple of 3 are:
21, 24, 27, 30, 33, 36 and 39
The number of favourable outcomes = 7
∴ Probability(getting a sum of digits is multiple of 3) =
=
iii) Divisible by 4 or 5
The numbers are divisible by 4 or 5:
24, 25,28, 30, 32, 35, 36 and 40
The number of favourable outcomes = 8
∴ Probability(getting a number divisible by 4 or 5) =
= =
Given : A box has cards with numbers 21, 22, 23 , 40.
A card is chosen at random.
To Find :What is the probability that the card chosen is
i) A prime number
ii) Sum of the digits is a multiple of 3
iii) Divisible by 4 or 5.
Solution:
A box has cards with numbers 21, 22, 23 , 40.
=> n(S) = 20
card chosen is A = prime number
23 , 29 , 31 , 37
n(A) = 4
Probability that the card chosen is prime number = n(A)/n(S) = 4/20 = 1/5
B = Sum of the digits is a multiple of 3
Hence number is multiple of 3
21 , 24 , 27 , 30 , 33 , 36 , 39
n(B) = 7
Probability that the card chosen has sum of the digits as a multiple of 3 = n(B)/n(S) =7/20
Divisible by 4 or 5.
= Divisible by 4 + Divisible by 5 - Divisible by 20
Divisible by 4 = 24 , 28 ,32 , 36 , 40
Divisible by 5 = 25 , 30 , 35 , 40
Divisible by 20 = 40
5 + 4 - 1 = 8
Probability that the card chosen Divisible by 4 or 5. = 8/20 = 2/5
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