a box has coupons numbered from 1 to 100.A coupon is picked.Find the probability that the number is a multiple of 3.
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no of coupon of multiple of 3 for an AP ,,as
3,6,9....……..99
here a=3, d=3 no terms
Last term is 99 so,
99=a+(n-1)d
99=3+(n-1)3
(n-1)=96/3=32
n=33
P(e)=33/100=.333
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