Question

A box is filled with 6 red cards, blue cards, 3 and 6 brown cards. A card is chosen at random from the box. What is the probability that it is a red or a brown card? Write your answer as a fraction in simplest form

Answer 1

Answer:

favourable outcomes/possible outcomes

=6/15

=2/5

Step-by-step explanation:

Answer 2

Answer:

No. of red cards = 6

No. of blue cards = 3

No. of brown cards = 6

Total no. of cards = 15

Let the probability of choosing card be 'E'

No. of times E occurs = 6 + 6 = 12

P(E) = No. of trials in which the event has happened

       -----------------------------------------------------------------------

                              Total no. of trials

P(E) =  $\frac{12}{15}$

      = $\frac{4}{5}$

∴ The probability the the card drawn is brown or red is  $\frac{4}{5}$