Question

A box is kept on a rough horizontal
surface. A horizontal force just strong
enough to move the box is applied. This
force is maintained for 2 seconds, and is
then removed. The total distance moved
by the box is S meters. Then find the
value of S.
Take: js = 0.2, uk 0.15 and
g=​

Answer 1

Answer:

Force responsible for increase in velocity =(μ

s

−μ

k

)mg

=(0.8−0.6)×4×10

=0.2×4×10

=8 N

Therefore, a=

4

8

=2 ms

−2