Question

A box is moving up an inclined plane of inclination 30 degree with a constant acceleration of 5 m/s square.A particle is projected with a velocity of 5root3 m/s inside a box at an angke of 30 degree wit the base.Then the time after which it again srrikes the same base if the box is

Answer 1

Explanation:

Given,

v = 20 m/s

angle = 60°

t = 2s

g = 10 m/

now we have to find  acceleration due to gravity

v = u +at

          [ u = 0 ]

a =

now lets find the coefficient of friction "z" - let's use this symbol to denote friction as we don't have the appropriate symbol here

mg sinβ + z(mg cosβ) = ma

mg [ sinβ + zcosβ ]  = ma

sinβ + z cosβ =

sinβ + z cosβ = 10/10

sinβ + z cosβ = 1

z =

z =

z = 2- =  co efficient of friction