Question

a box is pushed for 5 sec with force of 130 n the frictional force is 30 n calculate the final kinetic energy of the box??​

Answer 1

Answer:

125,000/m J

Explanation:

Let mass of the box be m

Time= t= 5 sec

Applied force= 130 N

Friction= 30 N

Net force= F= 130-30= 100 N

Momentum= P= F x t                              

                       = 100 x 5= 500 Nm/s²

We know that Kinetic energy = P² / 2m

                                                = (500)² /2m

                                               = 250,000/2m

                                               = 125,000/m J