a box m of mass 2kg is placed in an inclined surface with friction "f=6.7N" at what angle will the box be in equilibrium
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Mass = 2kg
f = 6.7 N
Assuming g = 10 m/
For the body to be in equilibrium,
f - mgsinΘ = 0 [Newton's second law of motion]
therefore,
f = mgsinΘ
6.7 = 2 * 10 * sinΘ
sinΘ = 6.7/20
sinΘ = 0.335
Θ = (0.335)
Θ ≈ 19.57 °
Hence, the inclination should be of 19.57 °
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I hope you understand.
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