Question

A box mass 55.0 kg is moving along the x-axis attached to a uniform spring of mass 6.50
kg and force constant 2500 N/m. Calculate the angular frequency of the box by
considering effect of mass of the spring.
​

Answer 1

Explanation:

We have,

m=1 kg, K=16 N/m

ω=

m

K

for a S.H.M

=

1

16

=4 rad/s

Also,

ω=2πn⇒n=

2π

ω

=

2π

4

=

π

2

Hz.

∴n=

3.14

2

=0.6369 Hz.

The angular frequency of the body is 4rad/s and the frequency of vibration is 0.6369 Hz.

Hence, this is the answer.