A box measure 20 inches long and 21 inches high.What is the diagonal length of the box?
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Answered by
5
By Pythagoras theorem,
20²+21²=diagonal²
400+441=diagonal ²
√841=diagonL
29= diagonal
20²+21²=diagonal²
400+441=diagonal ²
√841=diagonL
29= diagonal
Answered by
2
Use Pythagoras' Theorem:
c²=a²+b²
c²=20²+21²
c²=841
c=√841
c=29 inches
c²=a²+b²
c²=20²+21²
c²=841
c=√841
c=29 inches
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