A box of 1 litre capacity is divided into two equal compartments by a thin partition which are filled with 2 grams of hydrogen and 16 grams of methane respectively the pressure in compartment filled with hydrogen is recorded as p atm pressure when partition is removed will be
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Answer:
Pressure remains P.
Explanation:
From the question we get that the weight of hydrogen is 2 so the number of moles of hydrogen or n(H2) will be 1. The weight of the methane is 16 and the number of moles of methane or n(CH4) will be 16/16=1.
So, the pressure of the hydrogen will be P(H2) = (1/(1+1))*P which on solving we will get P/2. Also the pressure of the methane P(CH4) will also be 1/(1+1)P which will be P/2.
So, the total pressure will be P/2 + P/2 which is P.
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