A box of 12 dozen pens contains a dozen defective pens. One pen is taken
out at random. What is the probability that the pen taken out is
a) defective b) non - defective
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Answer:
the probability of taking a defective pen=1/12
the probability of taking a non-defective pen=11/12
Step-by-step explanation:
total pens 1 dozen = 12
total dozens = 12
total pens => 12*12=144
total defective pens = 12
total non - defective pens => 144-12 = 132
1) probability of taking out a defective pen = Number of outcomes/Total Number of outcomes
=> 12/144
= 1/12
2) probablity of taking out non - defective pen = Number of outcomes/Total Number of outcomes
=> 132/144
== 11/12
Hope it helps!
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