Question

A box of 160 electric bulbs contain 12 defective bulbs one bulb is taken out at random from the box what is the probability that the bulb is drawn 1)defective 2)non defective

Answer 1

Answer:

i)$\frac{3}{40}$ 2)$\frac{37}{40}$

Step-by-step explanation:

Total number of bulbs=160

1)Number of Defective bulbs=12

Probability of drawing a defective bulb=$\frac{12}{160}$=$\frac{3}{40}$

2)No.of Non-defective bulbs=160-12=148

  Probability of drawing a Non-defective bulb$=\frac{148}{160} =\frac{37}{40}$

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